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I have located two types of information on 8 pin optocouplers. I have the Vishay 6N datasheet. Assume this 6N to be used instead of a 4 pin optocoupler or a relay in a simple circuit where closure times must be short. Small amperage DC input to trigger larger DC amperage output circuit.
My questions are extremely basic.
6N137 Даташит / HP
Is this output connected to the negative side of the circuit you are closing? Or is this the output connected to the negative side of the circuit you are closing?
If not, what is it for? Q5 Pin 8 Vcc Collector Supply. I assume the positive side of the circuit to be closed when the optocoupler is activated is connected here? A direct answer to my questions would be wonderful. Direction to literature that describes specifically what I am asking would be helpful also. I could understand 8 pin optocoupler layout better if someone had a diagram of the inside a 6N optocoupler showing internal routing of all 8 of the pins. The datasheet does not seem to account for every pin.
Pin 6 is the open-collector output, i. To get a valid output voltage when the output is inactive, you have to connect a pull-up resistor. Pin 7 is not an emitter, but the enable inputi. Bias for the photo diode is decoupled from V CC to reduce the possibility of “chatter” oscillatory transition from one logic state to another due to regenerative coupling via the power supply line.
The linear amplifier has 6nn137 tendency to be unstable if the high-frequency impedance of the power supply is not low enough. For this reason, a low-inductance bypass capacitor 0. This, gp other chatter-suppression techniques are discussed in Section 3.
The Schottky clamp is a metal-silicon diode in parallel with the base-collector junction of the output transistor. A metal-silicon Schottky diode has a lower turn-on voltage than a P-N junction,so when the transistor is driven into saturation, the Schottky yp bypasses the current which would otherwise enter the base-collector junction.
opto isolator – 6N Optocoupler Pin Configuration – Electrical Engineering Stack Exchange
With reduced current entering the base-collector junction, there is a proportionate reduction in the charge to be removed when the transistor is to be turned off, and thus the Schottky clamp reduces the turn-off delay. The “enable” input has 6n1137 voltage and input current levels resembling a TTL input. However, it is not necessary to apply a pullup resistor to insure its remaining high. Unless the enable is connected to a strobe, it may simply be left open. The strobe applied to the enable input may be either open-collector or active-pullup.
With the enable high, analog operation is possible because there is no hysteresis. However, the dynamic range is limited. The lower limit is the threshold input current for operation in the active region — this threshold may be as high as 4 mA.
The upper limit is the maximum dissipation rating on the output. Because of a touchy bias situation, analog separation is not recommended for designs to be mass produced. The reason for omitting hysteresis was not to permit analog operation, but rather to permit maximum data rate. With hysteresis, there would be a higher immunity to both differential- hpp common-mode noise but the shifting threshold would reduce the data rate capability.
The effect of hysteresis on data rate is the opposite of peaking. Pin 7 Ve is an enable input. If it is held High or left unconnected, the device works. See the “Truth Table” on Page 2 of the Vishay datasheet. The 6N output side is something more than a simple transistor. The Vcc and Ground pins 8 and 5 provide operating power for the output circuit, and pin 6 is the 6n1137 of the output transistor.
HP 6n in Electronic Components & Semiconductors | eBay
The part will pull pin 6 to ground when the LED is lit, and let the output float when it is not lit. It is an open-drain used to pull-down some signal. So yes the “negative side of the circuit you are closing”. The is an Enable Input – No pull up resistor required as the device has an internal pull up resistor.
Pins 5 and 8 are the 5 V power supply pin 8 is not directly connected to a collector. Vishay’s 6N actually uses a Schmitt trigger to get hysteresis. This allows me to understand it much better! Since pin 7 is an enable input, why is at marked as Ve in the Vishay datasheet?
Also, does having the 5V power supply connected to pin 8 Positive and pin 4 Negative cause a continued power drain, as it measures as hot all the time? Varner Nov 5 ’17 at The supply current is specified in the datasheet. Nov 5 ’17 at Pins 1 and 4 are marked “NC” on the datasheet – 6m137 means “No Connection” – they are not used. Electrically n6137 are not used.
This seems to make sense. However, testing this on a breadboard I must not be applying this correctly. Varner Nov 2 ’17 at Pin5 is ground so you have just connected an LED straight across the supply.
NOTE this will stress teh device. I did already have the resistor in the circuit. This did 6n37 function when the input side was triggered. Just to be clear. The Absolute Maximum voltage for the output side between pins 8 and 5 is 7 volts – if you applied 9 volts, you may have killed the 6N Think of the output side of the 6N as a logic gate, not as a bp transistor – it must get power via its Vcc and Gnd pins.
When gp LED is lit, the output pin 6 will be pulled to Gnd. Look at the test circuits on page 5 of the Vishay datasheet. Sign up or log in Sign up using Google.